- 1. substr()
- 2. replace()
- 例子：split()
字符串切割： substr
函数原型：
string substr ( size_t pos = 0, size_t n = npos ) const;
解释：抽取字符串中从pos(默认为0)开始，长度为npos的子字串
#include <iostream> #include <string> using namespace std; int main() { string s = "hello";
cout << s.substr() << endl; cout << s.substr(2) << endl; cout << s.substr(2, 2) << endl;
cout << s.substr(2, string::npos) << endl; }
结果
hello
llo
ll
llo
注意：string 类将 npos 定义为保证大于任何有效下标的值
字符串替换：replace
函数原型：
|
1
2
|
basic string& replace(size_ type Pos1, size_type Num1,
const
type* Ptr );
basic string& replace(size_ type Pos1, size_type Num1,
const
string Str );
|
替换用Ptr(或str)替换字符串从Pos1开始的Num1个位置
#include <iostream> #include <string> using namespace std; int main() { string s = "hello"; string m = s.replace(1, 2, "mmmmm"); cout << m << endl; }
结果：hmmmmmlo
另
#include <iostream> #include <string> using namespace std; int main() { string s = "hello"; char a[] = "12345"; string m = s.replace(1, 2, a); cout << m << endl; }
结果：h12345lo
举例
split()函数
#include <iostream> #include <vector> using namespace std; vector<string> split(const string &s, const string &delim) { vector<string> elems; size_t pos = 0; size_t len = s.length(); size_t delim_len = delim.length(); if (delim_len == 0) { elems.push_back(s.substr(0, len)); return elems; } while (pos < len) { int find_pos = s.find(delim, pos); if (find_pos < 0) { elems.push_back(s.substr(pos, len-pos)); break; } elems.push_back(s.substr(pos, find_pos-pos)); pos = find_pos + delim_len; } return elems; } int main() { vector<string> vec = split("hello^nihao^ohyi", "^"); for (int i = 0; i < vec.size(); ++i) cout << vec[i] << endl; }
本文转自jihite博客园博客，原文链接：http://www.cnblogs.com/kaituorensheng/p/3891621.html，如需转载请自行联系原作者
