ZOJ1045&&1048

简介:
两道简单题,此外,1049有网友给出的计算公式是 Z=3.14*(x*x+y*y)/100.0+1.0,可惜我不明白其原理

ZOJ1045 HangOver

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#include<iostream>
using namespace std;
int main()
{
    double target,num,sum;
    while(cin>>target&&target!=0.00)
    {
        sum = 0.0f;
        num = 2;
        while(sum<target)
        {
            sum += 1.0/num;
            num++;
        }
        cout<<num-2<<" card(s)"<<endl;
    }
    return 0;
}
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 ZOJ1048 Financial Management

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#include<iostream>
using namespace std;
int main()
{
    double sum = 0.0f,average = 0.0f,num;
    for (int i=0;i<12;++i)
    {
        cin>>num;
        sum += num;
    }
    average = sum/12.0f;
    cout<<"$"<<average<<endl;
    return 0;
}
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本文转自Phinecos(洞庭散人)博客园博客,原文链接:http://www.cnblogs.com/phinecos/archive/2008/10/23/1318249.html,如需转载请自行联系原作者
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