hibernate+spring mvc, 解决hibernate 对象懒加载 json序列化问题

Java代码  

1. @RequestMapping("login")  
2.     @ResponseBody  
3.     public Object login(@RequestParam String username,@RequestParam String password){  
4.         List<User> list=userDAO.findByUsername(username);  
5.         if(list.size()>0){  
6.             User user=list.get(0);  
7.             if(user.getPassword().equals(password)){  
8.                 return new Result(user, "操作成功", true);  
9.             }else{  
10.                 return new Result(null, "密码错误", true);  
11.             }  
12.         }else{  
13.             return new Result(null, "用户未注册", false);  
14.         }  
15.     }  

Xml代码  

1. <filter>  
2.         <filter-name>openSession</filter-name>  
3.         <filter-class>org.springframework.orm.hibernate3.support.OpenSessionInViewFilter</filter-class>  
4.         <init-param>  
5.             <param-name>singleSession</param-name>  
6.             <param-value>false</param-value>  
7.         </init-param>  
8.     </filter>  
9.     <filter-mapping>  
10.         <filter-name>openSession</filter-name>  
11.         <url-pattern>/*</url-pattern>  
12.     </filter-mapping>  

Js代码  

1. {"message":"操作成功","results":{"language":null,"id":"402881e6421e40b601421e4111c60001","type":null,"extra":null,"time":null,"username":"wanggang","msg":null,"password":"138333","tag":null,"tel":null,"qq":null,"email":null,"gender":null,"lat":null,"lang":null,"point":null,"openid":null,"city":null,"photo":null,"notes":[],"chatsForUserTwoId":[],"attentionsForUserId":[],"attentionsForAttentionUserId":[],"logs":[],"chatsForUserOneId":[],"commentsForNoteId":[],"commentsForUserId":[]},"success":true}  

Java代码  

1. @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY, mappedBy = "user")  
2. @JsonIgnore  
3. public Set<Log> getLogs() {  
4.     return this.logs;  
5. }  
6.   
7. public void setLogs(Set<Log> logs) {  
8.     this.logs = logs;  
9. }  

Java代码  

1. @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.EAGER, mappedBy = "user")  
2.     public Set<Log> getLogs() {  
3.         return this.logs;  
4.     }  
5.   
6.     public void setLogs(Set<Log> logs) {  
7.         this.logs = logs;  
8.     }  

其实还有一种方法，就是jsonignore注解方法