在Python中向服务器提交一个表单数据看起来是很容易的,但是这次经历着实让我记忆深刻,借此也为了警醒同样遇到了这样问题的你们。
要做什么?
使用Python的urllib2模块提交表单数据,并在服务器端进行验证提交的表单结果。
操作系统
Windows 7 旗舰版需要的编译器:
- Eclipse
- PyCharm
- 需要的技术:
- (基础的)Java web技术
- (基础的)Python
服务器端代码
服务器端采用JavaWeb技术创建,使用Servlet来接收表单数据。具体内容如下:
首先是index.html:
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
</head>
<body>
<form action="GetParameters" method="POST">
<br>
UserName : <input type="text" name= "username"><br>
Password : <input type="password" name = "password"><br>
<br>
<input type= "submit" value="Submit">
<input type="reset">
</form>
</body>
</html>
然后是action对应的servlet界面。GetParameters.java
package one;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class GetParameters extends HttpServlet {
private static final long serialVersionUID = 1L;
/**
* @see HttpServlet#HttpServlet()
*/
public GetParameters() {
super();
// TODO Auto-generated constructor stub
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse
* response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// TODO Auto-generated method stub
response.getWriter().append("Served at: ").append(request.getContextPath());
doPost(request, response);
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse
* response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
// TODO Auto-generated method stub
// doGet(request, response);
String username = request.getParameter("username");
String password = request.getParameter("password");
System.out.println("Username is : " + username);
System.out.println("Password is : " + password);
response.getOutputStream().write("I have received you request!".getBytes());
}
}
最后就是web.xml的配置文件(我这里偷了个懒,老是记错配置,所以就在tomcat的一个sample 下面抄了一个,然后改了改,就成了)
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"
id="WebApp_ID" version="3.0">
<display-name>Test</display-name>
<welcome-file-list>
<welcome-file>index.html</welcome-file>
<welcome-file>index.htm</welcome-file>
<welcome-file>index.jsp</welcome-file>
<welcome-file>default.html</welcome-file>
<welcome-file>default.htm</welcome-file>
<welcome-file>default.jsp</welcome-file>
</welcome-file-list>
<servlet>
<servlet-name>GetParameters</servlet-name>
<servlet-class>one.GetParameters</servlet-class>
</servlet>
<!-- ... -->
<servlet-mapping>
<servlet-name>GetParameters</servlet-name>
<url-pattern>/GetParameters</url-pattern>
</servlet-mapping>
</web-app>
Python端代码
额,我姑且称之谓测试端吧。代码很简单,如下:
# coding:UTF-8
import sys,urllib,urllib2
def CommonWay():
url = 'http://localhost:8080/Test/GetParameters'
params = {
'username':'Username',
'password':'Password'
}
data = urllib.urlencode(params)
req = urllib2.Request(url,data)
response = urllib2.urlopen(req)
content = response.read()
print content
CommonWay()
print "Succeed!"
运行结果
Python控制台的输出结果是这样的
D:\Software\Python2\python.exe E:/Code/Python/GetWeather/ulib2/SubmitData.py
I have received you request!
Succeed!
Process finished with exit code 0
但其实最重要的就是服务器端的处理结果了。
我们可以在Eclipse的控制台清楚的看到我们提交的表单数据。至于要对这些数据做什么样的操作,就不是今天要讲的内容了。
总结
- 今天的收获很多,作为一个学习Python的新手,我坚信现阶段遇到的问题越多,进步的也就会越快。
- 对一个知识点要学的深入一点,而不只是停留在表面
- 少犯一些低级错误,比如我今天这个URL竟然都给弄错了。⊙﹏⊙b汗
- 多多的写代码,多多的测试,才能比较扎实的掌握。而不要图快,这样基础根本打不牢固。