hduoj2602Bone Collector

简介:  Bone Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 291...



Bone Collector

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 29163    Accepted Submission(s): 11922


Problem Description
Many years ago , in Teddy’s hometown there was a man who was called “Bone Collector”. This man like to collect varies of bones , such as dog’s , cow’s 
 also he went to the grave …
The bone collector had a big bag with a volume of V ,and along his trip of collecting there are a lot of bones , obviously , different bone has different value
and different volume, now given the each bone’s value along his trip , can you calculate out the maximum of the total value the bone collector can get ?

 


Input
The first line contain a integer T , the number of cases.
Followed by T cases , each case three lines , the first line contain two integer N , V, (N <= 1000 , V <= 1000 )representing the number of bones and the volume
of his bag. And the second line contain N integers representing the value of each bone. The third line contain N integers representing the volume of each bone.
 


Output
One integer per line representing the maximum of the total value (this number will be less than 2 31).
 


Sample Input
      
      
1 5 10 1 2 3 4 5 5 4 3 2 1
 


Sample Output
      
      
14
 翻译:有一人爱收集骨头,每个骨头有一个价值和重量,他有一个背包,容量为V,问他装得最大价值量是多少?(经典的01背包问题)

重点:01背包、动态规划
难点:动态方程的书写


#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int main()
{
	int T,n,v,i,j,dp[1100],a[1100],b[1100];//a[1100]是价值,b[1100]是重量;
	cin>>T;
	while(T--)
	{
		memset(a,0,sizeof(a));
		memset(b,0,sizeof(b)); 
		memset(dp,0,sizeof(dp)); 
		cin>>n>>v;//n是骨头个数,V是背包容量 
		for(i=1;i<=n;i++)
			scanf("%d",&a[i]);
		for(i=1;i<=n;i++)
			scanf("%d",&b[i]);
		for(i=1;i<=n;i++)
			for(j=v;j>=b[i];j--)
			{
				if(dp[j]<dp[j-b[i]]+a[i])
					dp[j]=dp[j-b[i]]+a[i];
			}
		printf("%d\n",dp[v]);
	}
	return 0;
}

目录
相关文章
|
3月前
|
Prometheus Kubernetes Cloud Native
Collector的配置和使用
Collector的配置和使用
62 1
|
6月前
|
Java
hdu-2602-Bone Collector
hdu-2602-Bone Collector
28 0
|
关系型数据库 MySQL Java
译 | Off-CPU Flame Graphs
译 | Off-CPU Flame Graphs
222 0
|
机器学习/深度学习 移动开发 自然语言处理
DEPPN:Document-level Event Extraction via Parallel Prediction Networks 论文解读
当在整个文档中描述事件时,文档级事件抽取(DEE)是必不可少的。我们认为,句子级抽取器不适合DEE任务,其中事件论元总是分散在句子中
126 0
DEPPN:Document-level Event Extraction via Parallel Prediction Networks 论文解读
|
算法 Linux Shell
SGAT丨Single Gene Analysis Tool
SGAT丨Single Gene Analysis Tool
|
人工智能 编解码 自动驾驶
YOLOv7: Trainable bag-of-freebies sets new state-of-the-art for real-time object detectors
YOLOv7在5 FPS到160 FPS的范围内,在速度和精度方面都超过了所有已知的物体检测器,在GPU V100上以30 FPS或更高的速度在所有已知的实时物体检测器中具有最高的精度56.8% AP。
460 0