题目
Given a string s consists of upper/lower-case alphabets and empty space characters ' '
, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World"
,
return 5
.
代码
public class Solution { public int lengthOfLastWord(String s) { if(s.length()==0) return 0; char[] chars=s.toCharArray(); char empty=' '; int lengthOfLastWord=0; int lengthOfLastWord_temp=0; for(int i=0;i<s.length();i++){ if(chars[i]!=empty){ lengthOfLastWord++; lengthOfLastWord_temp=lengthOfLastWord; } else { lengthOfLastWord=0; } } if(chars[s.length()-1]==empty) return lengthOfLastWord_temp; else return lengthOfLastWord; } }
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