a letter and a number
时间限制：
3000 ms | 内存限制：
65535 KB
难度：
1
- 描述
-
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).- 输入
- On the first line, contains a number T(0<T<=10000).then T lines follow, each line is a case.each case contains a letter x and a number y(0<=y<1000).
- 输出
- for each case, you should the result of y+f(x) on a line
- 样例输入
-
6 R 1 P 2 G 3 r 1 p 2 g 3
- 样例输出
-
19 18 10 -17 -14 -4
查看代码---运行号：252173----结果：Accepted
运行时间：
2012-10-05 11:36:47 | 运行人:
huangyibiao
01.
#include <iostream>
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using namespace std;
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int main()
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{
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int testNum;
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cin >> testNum;
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char letterX;
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int numY;
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while (testNum--)
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{
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cin >> letterX >> numY;
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if (letterX - 'a' >= 0)//小写
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{
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cout << numY - (letterX - 'a' ) - 1 << endl;//别忘了-1
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}
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else
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cout << numY + (letterX - 'A') + 1 << endl;//别忘了加1
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}
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return 0;
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}
