两数之间的 Armstrong 数

include

include

int main()
{
int low, high, i, temp1, temp2, remainder, n = 0, result = 0;

printf("输入两个整数: ");
scanf("%d %d", &low, &high);
printf("%d 和 %d 之间的 Armstrong 数为: ", low, high);

for(i = low + 1; i < high; ++i)
{
    temp2 = i;
    temp1 = i;

    // 计算
    while (temp1 != 0)
    {
        temp1 /= 10;
        ++n;
    }

    while (temp2 != 0)
    {
        remainder = temp2 % 10;
        result += pow(remainder, n);
        temp2 /= 10;
    }

    if (result == i) {
        printf("%d ", i);
    }

    n = 0;
    result = 0;

}
return 0;

}

运行结果：

输入两个整数: 100 1000
100 和 1000 之间的 Armstrong 数为: 153 370 371 407