将xml标签转换为txt(voc格式转换为yolo方便进行训练)
文章目录
- 将xml标签转换为txt(voc格式转换为yolo方便进行训练)
-
- 一、前言
- 二、程序
- 三、跑通演示
-
- 1、修改classes为你的数据集的classes
- 2、运行:输入图像与标注文件夹绝对地址
- 四、结果如下:
一、前言
检索一下其他人的之后,感觉没有我的好用,将自己的代码贡献一下
二、程序
import xml.etree.ElementTree as ET
import os
from os import listdir, getcwd
classes = ["bed", "water horse bucket"] # 换上你标签
def convert(size, box):
dw = 1.0 / size[0]
dh = 1.0 / size[1]
x = (box[0] + box[1]) / 2.0
y = (box[2] + box[3]) / 2.0
w = box[1] - box[0]
h = box[3] - box[2]
x = x * dw
w = w * dw
y = y * dh
h = h * dh
return (x, y, w, h)
def convert_annotation(image_name,labelPath):
# in_file = open(os.path.join(labelPath,image_name[:-3] + 'xml')) # xml文件路径
out_file = open(os.path.join(labelPath+'TXT',image_name[:-3] + 'txt'), 'w') # 转换后的txt文件存放路径
in_file = open(os.path.join(labelPath,image_name[:-3] + 'xml')) # xml文件路径
xml_text = in_file.read()
root = ET.fromstring(xml_text)
in_file.close()
size = root.find('size')
w = int(size.find('width').text)
h = int(size.find('height').text)
# print(root.iter('object'))
for obj in root.iter('object'):
cls = obj.find('name').text
if cls not in classes:
print(cls)
continue
cls_id = classes.index(cls)
xmlbox = obj.find('bndbox')
b = (float(xmlbox.find('xmin').text), float(xmlbox.find('xmax').text), float(xmlbox.find('ymin').text),
float(xmlbox.find('ymax').text))
bb = convert((w, h), b)
#print(bb)
out_file.write(str(cls_id) + " " + " ".join([str(a) for a in bb]) + '\n')
wd = getcwd()
if __name__ == '__main__':
imgNmae=input('输入图像文件夹的绝对地址:')
labelPath=input('输入xml标注的文件夹的绝对地址:')
#imgNmae='E:\数据集\新建文件夹//bed//bed\data\img'
#labelPath='E:\数据集\新建文件夹//bed/bed\data\labels'
if not os.path.isdir(labelPath+'TXT'):
os.mkdir(labelPath+'TXT')
for image_path in os.listdir(imgNmae): # 每一张图片都对应一个xml文件这里写xml对应的图片的路径
#image_name = image_path.split('\\')[-1]
print(image_path)
convert_annotation(image_path,labelPath)