技术经验分享:HDU4813HardCode

简介: 技术经验分享:HDU4813HardCode

"

Hard Code

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)

Total Submission(s): 1520 Accepted Submission(s): 1103

Problem Description

Some strange code is sent to Da Shan High School. It's said to be the prophet's note. The note is extremely hard to understand. However, Professor Meng is so smart that he successfully found the pattern of the code. That is, the length of the code is the product of two prime numbers. He tries to reallocate the code into a grid of size N*M, where M is the bigger prime. In specific, he writes down the letters of the code to the cells one by one, from left to right, and from top to button. //代码效果参考:https://v.youku.com/v_show/id_XNjQwNjg1Mzc5Mg==.html

In this way, he found the code eventually readable.

Professor Meng wants to know all the secrets of the note right now. But he doesn't take his computer with him. Can you help him?

Input

The first line of the input is L (L ≤ 1000), which means the number of test cases.

For each test case, the first line contains two prime numbers, which indicates N, M (0 < N M ≤ 1000) as describe above. The second line contains a string, i.e., the code, containing only lowercase letters. It’s guaranteed the length of the string equals to N M.

Output

For each test case, output N lines, each line with M letters representing the readable code after the reallocation.

Sample Input

1

2 5

klmbbileay

Sample Output

klmbb

ileay

Source

2013 Asia Regional Changchun

#include

#include

using namespace std;

int main()

{

int L;

cin]L;

//代码效果参考:https://v.youku.com/v_show/id_XNjQwNjg1MzczNg==.html

while(L--)

{

int m,n;

cin]n]m;

string s;

cin]s;

for(int i=0;i

{

cout[s【i】;

if((i+1)%m == 0)

cout[endl;

}

}

return 0;

}


"
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