从一个数组中拿到另一个数组中的值

现在有两个数组，数组a中有两个目标id值，数组b中是原数组，需求：想要从b数组中拿到含有a数组中id的值

 const a =[1,5]
  const b =[
    {
   id:1,sector:'技术部',name:'高工',createTime:'2022-02-10'},
    {
   id:2,sector:'测试部',name:'张工',createTime:'2022-02-10'},
    {
   id:3,sector:'技术部',name:'李工',createTime:'2022-02-10'},
    {
   id:4,sector:'测试部',name:'王工',createTime:'2022-02-10'},
    {
   id:5,sector:'技术部',name:'高工',createTime:'2022-02-10'},
  ]
  const c=[]

解法一：forEach方法

  a.forEach((pa)=>{
   
    b.forEach((pb)=>{
   
      if(pa === pb){
   
        c.push(pb.name)
      }
    })
  })

解法二：filter

  const c = b.filter((p)=>{
    if(a.includes(p.id)){
   
      return true;
    }
    return false;
  })