Python 递归检测文件夹下的文件

import os
# 查找指定文件夹下所有相同名称的文件
def search_file(dirPath, fileName):
    dirs = os.listdir(dirPath)  # 查找该层文件夹下所有的文件及文件夹，返回列表
    for currentFile in dirs:  # 遍历列表
        absPath = dirPath + '/' + currentFile
        if os.path.isdir(absPath):  # 如果是目录则递归，继续查找该目录下的文件
            search_file(absPath, fileName)
        elif currentFile == fileName:
            print(absPath)  # 文件存在，则打印该文件的绝对路径

if __name__ == "__main__":
    dirPath = 'D:\Sprider\HuaJunCode\\Temp'
    fileName4 = '服务器软件.url'
    fileName3 = '脚本之家.url'
    fileName1 = '说明.htm'
    fileName2 = 'Readme-说明.htm'
    fileName5 = 'jb51.net.txt'
    search_file(dirPath, fileName1)
    search_file(dirPath, fileName2)
    search_file(dirPath, fileName3)
    search_file(dirPath, fileName4)
    search_file(dirPath, fileName5)
    search_file(dirPath, "源码之家说明.txt")
    search_file(dirPath, "服务器常用软件.html")
    search_file(dirPath, "访问脚本之家.html")