leetcode-SQL-1303. 求团队人数

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| employee_id   | int     |
| team_id       | int     |
+---------------+---------+
employee_id 字段是这张表的主键，表中的每一行都包含每个员工的 ID 和他们所属的团队

Employee Table:
+-------------+------------+
| employee_id | team_id    |
+-------------+------------+
|     1       |     8      |
|     2       |     8      |
|     3       |     8      |
|     4       |     7      |
|     5       |     9      |
|     6       |     9      |
+-------------+------------+
Result table:
+-------------+------------+
| employee_id | team_size  |
+-------------+------------+
|     1       |     3      |
|     2       |     3      |
|     3       |     3      |
|     4       |     1      |
|     5       |     2      |
|     6       |     2      |
+-------------+------------+
ID 为 1、2、3 的员工是 team_id 为 8 的团队的成员，
ID 为 4 的员工是 team_id 为 7 的团队的成员，
ID 为 5、6 的员工是 team_id 为 9 的团队的成员。

select 
    employee_id,
    count(team_id) over(partition by team_id) as team_size
from Employee;

select a.employee_id,b.team_size
from Employee as a
left join(
    select
        team_id,count(*) as team_size
    from Employee
    group by team_id
)as b
on a.team_id=b.team_id;