因为自己写api定义了一套格式，但是django rest_framework的异常提醒又跟我的不一样，
要么是：
要么是
{ "detail":"身份错误" }
实在是不统一！！！
如果不修改，前端调用的时候就得多写点逻辑，或者强迫症极度不适应
于是就有了这篇文章。
我看了下，网上对于这样的情况，没有针对的指出，所以特地的发表这篇问题。
嗯，drf关于异常处理写个了方法
def exception_handler(exc, context): """ Returns the response that should be used for any given exception. By default we handle the REST framework `APIException`, and also Django's built-in `Http404` and `PermissionDenied` exceptions. Any unhandled exceptions may return `None`, which will cause a 500 error to be raised. """ if isinstance(exc, Http404): exc = exceptions.NotFound() elif isinstance(exc, PermissionDenied): exc = exceptions.PermissionDenied() if isinstance(exc, exceptions.APIException): headers = {} if getattr(exc, 'auth_header', None): headers['WWW-Authenticate'] = exc.auth_header if getattr(exc, 'wait', None): headers['Retry-After'] = '%d' % exc.wait if isinstance(exc.detail, (list, dict)): data = exc.detail else: data = {'detail': exc.detail} set_rollback() return Response(data, status=exc.status_code, headers=headers) return None
这里出现detail的！！！！
而我们要做的，就是重写异常的方法
REST_FRAMEWORK = { ... 'EXCEPTION_HANDLER': 'exception.handler.custom_exception_handler', .... }
然后去获取这个detail，并且删除不必要的提示
from rest_framework.views import exception_handler def custom_exception_handler(exc, context): response = exception_handler(exc, context) if response is not None: data = response.data.copy() response.data.clear() text = '' for k, v in data.items(): text += f'{k}: {v}' response.data['error'] = text return response
经过这样的处理，
就能变成这样的干净
