C++深度优先(DFS)算法的应用：收集所有金币可获得的最大积分

class CNeiBo2
{
public:
CNeiBo2(int n, bool bDirect, int iBase = 0):m_iN(n),m_bDirect(bDirect),m_iBase(iBase)
{
m_vNeiB.resize(n);
}
CNeiBo2(int n, vector<vector>& edges, bool bDirect,int iBase=0) :m_iN(n), m_bDirect(bDirect), m_iBase(iBase)
{
m_vNeiB.resize(n);
for (const auto& v : edges)
{
m_vNeiB[v[0]- iBase].emplace_back(v[1]- iBase);
if (!bDirect)
{
m_vNeiB[v[1]- iBase].emplace_back(v[0]- iBase);
}
}
}
inline void Add(int iNode1, int iNode2)
{
iNode1 -= m_iBase;
iNode2 -= m_iBase;
m_vNeiB[iNode1].emplace_back(iNode2);
if (!m_bDirect)
{
m_vNeiB[iNode2].emplace_back(iNode1);
}
}
const int m_iN;
const bool m_bDirect;
const int m_iBase;
vector<vector> m_vNeiB;
};
class Solution {
public:
int maximumPoints(vector<vector>& edges, vector& coins, int k) {
m_iK = k;
for (int i = 0; i < m_iN; i++)
{
m_vRet[i].assign(coins.size(),-1);
}
CNeiBo2 neiBo(coins.size(),edges, false);
dfs(0, -1, 0, neiBo, coins);
return m_vRet[0][0];
}
int dfs(int cur, const int parent, int split,const CNeiBo2& vNeiBo,const vector& coins)
{
if (split >= 20)
{
return 0;
}
int& iRet = m_vRet[split][cur];
if (-1 != iRet)
{
return iRet;
}
const int curCoin = coins[cur] / (1 << split);
int iType1 = curCoin - m_iK;
{
for (const auto& next : vNeiBo.m_vNeiB[cur])
{
if (parent == next)
{
continue;
}
iType1 += dfs(next, cur, split, vNeiBo, coins);
}
}
int iType2 = curCoin/2;
{
for (const auto& next : vNeiBo.m_vNeiB[cur])
{
if (parent == next)
{
continue;
}
iType2 += dfs(next, cur, split+1, vNeiBo, coins);
}
}
iRet = max(iType1, iType2);
return iRet;
}
int m_iK;
static const int m_iN = 20;
vector m_vRet[m_iN];//m_vRet[0] 未减半各节点及子孙节点的分数 m_vRet[i] 减半i次后的最大分数
};

template
void Assert(const vector& v1, const vector& v2)
{
if (v1.size() != v2.size())
{
assert(false);
return;
}
for (int i = 0; i < v1.size(); i++)
{
assert(v1[i] == v2[i]);
}
}
template
void Assert(const T& t1, const T& t2)
{
assert(t1 == t2);
}
int main()
{
Solution slu;
vector<vector> edges;
vector coins;
int k;
int res;
edges = { {0,1},{1,2},{2,3} };
coins = { 10,10,3,3 };
k = 5;
res = slu.maximumPoints(edges, coins,k);
Assert(11, res);
edges = { {0,1},{0,2} };
coins = { 8,4,4 };
k = 0;
res = slu.maximumPoints(edges, coins, k);
Assert(16, res);