倘若A代表人生的成功，那么公式是：A =X+Y+Z。X是工作，Y是游戏，z是保持缄默。——（美）爱因斯坦
我们以前从一个数组中获取第一项，可能是如下写法：
let list = [1,2,3] let i = list[0]
有了解构赋值，可以如下写法：
let list = [1,2,3] let [i] = list
如果稍微复杂点，例如下面这样从对象中取出来数组：
let ruben = {hobby:['anime']} let favorite = ruben.hobby[0]
就可以写成：
let ruben = {hobby:['anime']} let {hobby:[favorite]} = ruben
如果再复杂点
let ruben = {hobby:['anime']} let achao = {favorite:undefined} achao.favorite = ruben.hobby[0]
可以写成
let ruben = {hobby:['anime']} let achao = {favorite:undefined} [achao.favorite] = ruben.hobby
以及
let ruben = {hobby:['anime']}; let achao = {favorite:undefined}; ({hobby:[achao.favorite]} = ruben);
关键在于，两边的结构要一致，而且不能使用{}作为代码开头，会被解析为代码块
我们最后来一个收尾
let ruben = {hobby:[{english:'ruben',chinese:'阿超',behavior:()=>'看动漫'}]}; let achao = {weekend:{todo:undefined},names:[]}; achao.weekend.todo = ruben.hobby[0].behavior; achao.names = [ruben.hobby[0].english,ruben.hobby[0].chinese];
写成：
let ruben = {hobby:[{english:'ruben',chinese:'阿超',behavior:()=>'看动漫'}]}; let achao = {weekend:{todo:undefined},names:[]}; ({hobby:[{english:achao.names[0],chinese:achao.names[1],behavior:achao.weekend.todo}]} = ruben);
