数组拷贝问题：api接口

#include <iostream>
#include <string.h>
using namespace std;
int get_Array(char **srcp1 , int num1, char (*srcp2)[20] , int num2 , char ***ans,int *mynum)
{
    int ret=0 ;
    int num=0;
    char **tmp = NULL;
    if(srcp1 == NULL || srcp2 == NULL || mynum == NULL)
    {
        ret = -1;
        printf("srcp1 == NULL || srcp2 == NULL || mynum == NULL \n");
        return ret;
    }
    //准备在堆上分配内存
    //num = num1 + num2;
    printf("%d\n",num);
    //分配指针数组的内存
    tmp = (char **)malloc(sizeof(char *)*num);
    if(tmp == NULL)
    {
        ret -2;
        printf("tmp == NULL:(char **)malloc(sizeof(char *)*num) \n");
        return -1;
    }
    //分配第二堆内存-->第一钟
    for(int i=0;i<num1;i++)
    {
        tmp[i] = (char *)malloc(strlen(srcp1[i])+1);
        if(tmp[i]==NULL)
        {
            ret = -3;
            printf("tmp[%d]==NULL:(char *)malloc(strlen(srcp1[i])+1)\n",i);
            return ret;
        }
        strcpy(tmp[i],srcp1[i]);
    }
    //分配第二堆内存-->第二钟
     for(int i=0;i<num2;i++)
    {
        tmp[i] = (char *)malloc(strlen(srcp2[i])+1);
        if(tmp[i]==NULL)
        {
            ret = -4;
            printf("tmp[%d]==NULL:(char *)malloc(strlen(srcp2[i])+1)\n",i);
            return ret;
        }
        strcpy(tmp[i],srcp2[i]);
    }
    *ans = tmp;
    *mynum = num;
    return 0;
}
int  get_Array_Free(char ***p , int numlen)
{
    int i;
    char **tmp = NULL;
    if(p==NULL)
    {
        printf("p==NULL\n");
        return -1;
    }
    tmp = *p;
    for(i =0 ;i<numlen;i++)
    {
        if(tmp[i] != NULL)
        {
            free(tmp[i]);
        }
    }
    free(tmp);
    *p = NULL;   //避免野指针
}
int  main()
{
    int ret  = 0;
    int mynum = 0;
    char *p1[] = {"1111","222","4444","5555555"};
    char p2[4][20] = {"bbbb" , "aaaaa" ,"22222" ,"cccccc"};
    char **p3=NULL;
    ret = get_Array(p1,4,p2,4,&p3,&mynum);
    if(ret != 0)
    {
        printf("get_Array error:ret \n",ret);
    }
    for(int i=0;i<mynum;i++)
            printf("%s\n",p3[i]);
    get_Array_Free(&p3 , mynum);
    return 0;
}