带你读《图解算法小抄》十五、搜索（2）

/**
 * Interpolation search implementation.
 *
 * @param {*[]} sortedArray - sorted array with uniformly distributed values
 * @param {*} seekElement
 * @return {number}
 */export default function interpolationSearch(sortedArray, seekElement) {
  let leftIndex = 0;
  let rightIndex = sortedArray.length - 1;
  while (leftIndex <= rightIndex) {
    const rangeDelta = sortedArray[rightIndex] - sortedArray[leftIndex];
    const indexDelta = rightIndex - leftIndex;
    const valueDelta = seekElement - sortedArray[leftIndex];
    // If valueDelta is less then zero it means that there is no seek element
    // exists in array since the lowest element from the range is already higher
    // then seek element.
    if (valueDelta < 0) {
      return -1;
    }
    // If range delta is zero then subarray contains all the same numbers
    // and thus there is nothing to search for unless this range is all
    // consists of seek number.
    if (!rangeDelta) {
      // By doing this we're also avoiding division by zero while
      // calculating the middleIndex later.
      return sortedArray[leftIndex] === seekElement ? leftIndex : -1;
    }
    // Do interpolation of the middle index.
    const middleIndex = leftIndex + Math.floor((valueDelta * indexDelta) / rangeDelta);
    // If we've found the element just return its position.
    if (sortedArray[middleIndex] === seekElement) {
      return middleIndex;
    }
    // Decide which half to choose for seeking next: left or right one.
    if (sortedArray[middleIndex] < seekElement) {
      // Go to the right half of the array.
      leftIndex = middleIndex + 1;
    } else {
      // Go to the left half of the array.
      rightIndex = middleIndex - 1;
    }
  }
  return -1;
}