使用openpyxl库断言导出数据的接口

def test_Staffexport(self):
        url = common.Consts.url_lms_test + "url/export?current=1&size=10&deptId=932"
        header = {
            "Accept": 'application/json, text/plain, */*',
            "Accept-Language": "zh-CN,zh;q=0.9",
            "Accept-Encoding": "gzip, deflate, br",
            "Cookie": "trackType=web;XXXXXXX"
        }
        r = requests.get(url=url, headers=header)
        from pathlib import Path
        #获取当前文件的前文件夹上两层路径
        BASE_DIR = Path(__file__).resolve().parent.parent.parent #/Users/xmly/college-autotest
        print(BASE_DIR)
        #拼接路径，组成导出表格需要保存的位置
        data_path = os.path.join(BASE_DIR,'data/staff.xlsx')
        print(data_path) # /Users/xmly/college-autotest/data/staff.xlsx
        with open(data_path, mode="wb+") as f:
            f.writelines(r)
        # 忽略默认样式警告，不影响运行
        warnings.filterwarnings('ignore')
        wb = openpyxl.load_workbook(data_path)
        ws = wb['Sheet0']
        #获取单元格中第2行第1列的数据
        val = ws.cell(2, 1).value
        #断言获取到的数据与预期结果是否一样
        assert val == 预期结果