$arr = [[ "objid" => "22249", "device" => "192.168.0.202", "datetime" => "2021/3/15 12:52:17", "datetime_raw" => 44270.2029801968, "sensor" => "内存1", "status" => "正常运行", "status_raw" => 3, "lastvalue" => "89", "lastvalue_raw" => "89" ], [ "objid" => "22250", "device" => "192.168.0.202", "datetime" => "2021/3/15 12:52:17", "datetime_raw" => 44270.2029801968, "sensor" => "内存2", "status" => "正常运行", "status_raw" => 3, "lastvalue" => "74", "lastvalue_raw" => "89" ], [ "objid" => "22250", "device" => "192.168.0.202", "datetime" => "2021/3/15 12:52:17", "datetime_raw" => 44270.2029801968, "sensor" => "内存2", "status" => "正常运行", "status_raw" => 3, "lastvalue" => "34", "lastvalue_raw" => "89" ]];
项目需求
遍历数据，求包含“内存”字段的lastvalue，求和。
for ($i = 0; $i < count($arr); $i++) { if (stripos($arr[$i]["sensor"], "内存") !== false) { $cpu[$i] = $arr[$i]["lastvalue"]; } } echo "<pre>"; var_dump($cpu); $data["cpu"] = round(array_sum($cpu) / count($cpu), 1);
lockdatav Done!
