python脚本两个文件夹里的文件名对比找出不同图片和标签

# 图片文件夹和标签文件夹对比
# -*- coding: utf-8 -*-
import os
# path1和path2分别列出两个文件夹路径，自己根据情况更换
path1 = r'C:\pyworkplace\VOCdevkit\VOC2007\JPEGImages'
path2 = r'C:\pyworkplace\VOCdevkit\VOC2007\Annotations'
def file_name(image_dir,xml_dir):
    jpg_list = []
    xml_list = []
    for root, dirs, files in os.walk(image_dir):
        for file in files:
            jpg_list.append(os.path.splitext(file)[0])
    for root, dirs, files in os.walk(xml_dir):
        for file in files:
            xml_list.append(os.path.splitext(file)[0])
    print(len(jpg_list))
    diff = set(xml_list).difference(set(jpg_list))  # 差集，在a中但不在b中的元素
    for name in diff:
        print("no jpg", name + ".xml")
    diff2 = set(jpg_list).difference(set(xml_list))  # 差集，在b中但不在a中的元素
    print(len(diff2))
    for name in diff2:
        print("no xml", name + ".jpg")
if __name__ == '__main__':
    file_name(path1,path2)