Json解析问题—数组用Gson反序列化为List双引号消失

简介: 现在的目的是这样的,我想从一串Object类型的字符串,转化成对应的实体类对象。简单来说就是把这个字符串给一个个独立分开。我先写出实体类对象和Json的数据,看完再开始解析。

现在的目的是这样的,我想从一串Object类型的字符串,转化成对应的实体类对象。


简单来说就是把这个字符串给一个个独立分开。


我先写出实体类对象和Json的数据,看完再开始解析。


实体类对象

package com.yyt.accountbooks.db.model;
import androidx.room.Entity;
import androidx.room.PrimaryKey;
/**
 * @ projectName:   AccountBooks
 * @ packageName:   com.yyt.accountbooks.model
 * @ fileName:      BillModel
 * @ author:        zheng
 * @ createTime:    2023/1/11 17:32
 * @ describe:      账本表对象
 */
@Entity(tableName = "bills")
public class BillModel {
    /**
     * balance : 0.0
     * createTime : 1660880757000
     * id : 2
     * income : 0.0
     * name : 账本一
     * params : {}
     * pay : 0.0
     * remark : 账本备注
     * uid : 12
     */
    @PrimaryKey
    private int id;
    private double balance;
    private long createTime;
    private double income;
    private String name;
    private double pay;
    private String remark;
    private int uid;
    public double getBalance() {
        return balance;
    }
    public void setBalance(double balance) {
        this.balance = balance;
    }
    public long getCreateTime() {
        return createTime;
    }
    public void setCreateTime(long createTime) {
        this.createTime = createTime;
    }
    public int getId() {
        return id;
    }
    public void setId(int id) {
        this.id = id;
    }
    public double getIncome() {
        return income;
    }
    public void setIncome(double income) {
        this.income = income;
    }
    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public double getPay() {
        return pay;
    }
    public void setPay(double pay) {
        this.pay = pay;
    }
    public String getRemark() {
        return remark;
    }
    public void setRemark(String remark) {
        this.remark = remark;
    }
    public int getUid() {
        return uid;
    }
    public void setUid(int uid) {
        this.uid = uid;
    }
    @Override
    public String toString() {
        return "BillModel{" +
                "balance=" + balance +
                ", createTime=" + createTime +
                ", id=" + id +
                ", income=" + income +
                ", name='" + name + '\'' +
                ", pay=" + pay +
                ", remark='" + remark + '\'' +
                ", uid=" + uid +
                '}';
    }
}


Json数据


因为getData()的类型是Object的,获得的是data后面部份的数组,一共有13个数组对象


string:{"code":0,"data":[{"balance":0.00,"createTime":1660880757000,"id":2,"income":0.00,"name":"账本一","params":{},"pay":0.00,"remark":"账本备注","uid":12},
{"balance":0.00,"createTime":1673076697000,"id":4,"income":0.00,"name":"pppppp","params":{},"pay":0.00,"remark":"pppppp","uid":12},
{"balance":0.00,"createTime":1673077667000,"id":5,"income":0.00,"name":"账本一","params":{},"pay":0.00,"remark":"账本一","uid":12},
{"balance":0.00,"createTime":1673077687000,"id":6,"income":0.00,"name":"账本一","params":{},"pay":0.00,"remark":"账本一","uid":12},
{"balance":0.00,"createTime":1673077696000,"id":7,"income":0.00,"name":"坎坎坷坷看看","params":{},"pay":0.00,"remark":"坎坎坷坷看看","uid":12},
{"balance":0.00,"createTime":1673079793000,"id":8,"income":0.00,"name":"账本一","params":{},"pay":0.00,"remark":"账本一","uid":12},
{"balance":0.00,"createTime":1673080112000,"id":9,"income":0.00,"name":"账本一","params":{},"pay":0.00,"remark":"账本一","uid":12},
{"balance":0.00,"createTime":1673080305000,"id":10,"income":0.00,"name":"哈哈哈哈哈那就","params":{},"pay":0.00,"remark":"哈哈哈哈哈那就","uid":12},
{"balance":0.00,"createTime":1673080319000,"id":11,"income":0.00,"name":"账本一","params":{},"pay":0.00,"remark":"账本一","uid":12},
{"balance":0.00,"createTime":1673080812000,"id":12,"income":0.00,"name":"账本一","params":{},"pay":0.00,"remark":"账本一","uid":12},
{"balance":0.00,"createTime":1673082156000,"id":13,"income":0.00,"name":"账本一","params":{},"pay":0.00,"remark":"账本一","uid":12},
{"balance":0.00,"createTime":1673086473000,"id":14,"income":0.00,"name":"用英语","params":{},"pay":0.00,"remark":"探讨探讨","uid":12},
{"balance":0.00,"createTime":1673088234000,"id":15,"income":0.00,"name":"滚滚滚","params":{},"pay":0.00,"remark":"","uid":12}]}


Gson库解析


错误思路1


直接把Object类型的Json数据直接反序列化为实体类的数组对象。

BillModel[] billModels =gson.fromJson((responseModel.getData().toString())
                                        ,BillModel[].class);


解析直接错误,解都解不出来.....


至于为什么?


应该是Object类型的数据直接toString不行。

目录
相关文章
|
24天前
|
JSON JavaScript 前端开发
C++ 智能指针与 JSON 处理:高级编程技巧与常见问题解析
C++ 智能指针与 JSON 处理:高级编程技巧与常见问题解析
254 0
|
15天前
|
存储 算法
从动态规划到贪心算法:最长递增子序列问题的方法全解析
从动态规划到贪心算法:最长递增子序列问题的方法全解析
16 2
|
24天前
|
JSON JavaScript 数据格式
【深入探究C++ JSON库】解析JSON元素的层级管理与遍历手段
【深入探究C++ JSON库】解析JSON元素的层级管理与遍历手段
78 2
|
24天前
|
XML JSON API
深入解析C++ JSON库:nlohmann::json:: parse的内部机制与应用
深入解析C++ JSON库:nlohmann::json:: parse的内部机制与应用
42 0
|
29天前
|
JSON 数据格式
人脸检测解析json的工具类face_test
人脸检测解析json的工具类face_test
13 0
|
1月前
|
JSON JavaScript 前端开发
如何在Python中解析JSON响应?
【2月更文挑战第26天】【2月更文挑战第92篇】如何在Python中解析JSON响应?
|
1月前
|
JSON Java Maven
使用Jackson进行 JSON 序列化和反序列化
使用Jackson进行 JSON 序列化和反序列化
23 0
|
1月前
|
JSON JavaScript 前端开发
Qt 5.14.2 深度解析:打造高效JSON处理利器
Qt 5.14.2 深度解析:打造高效JSON处理利器
|
1月前
|
存储 JSON JavaScript
Python中读写(解析)JSON文件的深入探究
Python中读写(解析)JSON文件的深入探究
24 0
|
1月前
|
存储 JSON JavaScript
Python如何解析json对象?
Python如何解析json对象?
23 1

热门文章

最新文章

推荐镜像

更多