二进制加法

#include <stdio.h>voidshowArray(intarray[], intlen);
intmain(void)
{
/*n位2进制整数相加问题(此处n=3)*/inta[] = {1, 1, 1, 1}, b[] = {1, 0, 0, 1}, c[] = {0, 0, 0, 0, 0}, len=3;
for (inti=len, j=len+1; i>=0; i--, j--)
    {
intxor=a[i] ^b[i];
//当前位进行异或运算c[j] =c[j] ^xor;
//2021-08-28 11:49:00 算出前一位，只使用位运算符似乎无法做到，留待后期考虑，此处不纠结c[j-1] = (a[i] +b[i] +c[j]) /2;
    }
printf("arry a is \n");
showArray(a, 3);
printf("arry b is \n");
showArray(b, 3);
printf("arry c is \n");
showArray(c, 4);
}
voidshowArray(intarray[], intlen)
{
for (inti=0; i<=len; i++)
    {
printf("%3d", array[i]);
    }
printf("\n");
}