/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* traversal(TreeNode* cur , int key)
{
//当为空节点的时候直接返回
if(cur==nullptr) return cur;
//当前值为目标值时
if(cur->val == key)
{
//当前点的左右子树都是空,删除节点返回
if(cur->left == nullptr && cur->right == nullptr)
{
delete cur;
return nullptr;
}
//左子树存在,右子树空,左孩子作为新的根节点返回
else if(cur->left != nullptr && cur->right == nullptr)
{
auto tmp = cur->left;
delete cur;
return tmp;
}
//左子树为空,右子树存在,右子树作为新的根节点返回
else if(cur->left == nullptr && cur->right != nullptr)
{
auto tmp = cur->right;
delete cur;
return tmp;
}
//左右子树都存在,令右孩子为新的根节点,左子树放到右子树的最左边。
else
{
TreeNode* tmp = cur->right;
while(tmp->left !=nullptr)
{
tmp = tmp->left;
}
tmp->left = cur->left;
TreeNode* result = cur->right;
delete cur;
return result;
}
}
//当前值不是目标值,按照二叉搜索树单边遍历
if(cur->val > key) cur->left = traversal(cur->left , key);
if(cur->val < key) cur->right = traversal(cur->right , key);
return cur;
}
TreeNode* deleteNode(TreeNode* root, int key) {
if(root==nullptr) return nullptr;
return traversal(root,key);
}
};