二叉树的层次遍历II
和102 一样,最后加一个反转即可
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode() : val(0), left(nullptr), right(nullptr) {} * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {} * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {} * }; */ class Solution { public: vector<vector<int>> levelOrderBottom(TreeNode* root) { vector<vector<int>> result; queue<TreeNode* > my_que; TreeNode* node = root; if(root == nullptr) return result; else { my_que.push(root); } while(my_que.empty() != 1) { int size = my_que.size(); vector<int> nums; for(int i=0 ; i<size ;i++ ) { node = my_que.front(); my_que.pop(); nums.push_back(node->val); if(node->left != nullptr) my_que.push(node->left); if(node->right != nullptr) my_que.push(node->right); } result.push_back(nums); } //和正常的层次遍历二叉树,多一个反转 reverse(result.begin(),result.end()); return result; } };