深度之眼（九）——python函数--面向过程的编程（下）

# 获取原始数据
    proh_A = eval(input("请输入运动员A的每球(0~1):"))
    proh_B = round(1-proh_A, 2)
    number_of_games = eval(input("请输入模拟的场次（正整数）："))
    print("模拟比赛总次数：",number_of_games)
    print("A 选手每球获胜的概率：",proh_A)
    print("B 选手每球获胜的概率：",proh_B)
    return proh_A,proh_B,number_of_games
def game_over(score_A, score_B):
    #单场模拟结束条件，一方达到21分，比赛结束
    return score_A == 21 or score_B == 21
def sim_one_game(proh_A, proh_B):
    #模拟一场比赛结果
    score_A, score_B = 0, 0
    while not game_over(score_A, score_B):
        if random.random() < proh_A:   # random.random()产生[0,1）之间的随机小数，均匀分布
            score_A += 1
        else:
            score_B += 1
    return score_A, score_B
# score_A, score_B = sim_one_game(0.7,0.3)
# print(score_A)
# print(score_B)
def sim_n_games(proh_A, proh_B, number_of_games):
    #模拟多场比赛的结果
    win_A, win_B = 0, 0
    for i in range(number_of_games):
        score_A, score_B = sim_n_games(proh_A, proh_B, number_of_games)
        if score_A > score_B:
            win_A += 1
        else:
            win_B += 1
    return win_A, win_B
def print_summer(win_A, win_B, number_of_games):
    # 结果汇总输出
    print("共模拟{}场比赛",format(number_of_games))
    print("\033[31m选手A获胜{0}场",format(win_A,win_A/number_of_games))
    print("选手B获胜{0}场，占比{1:.1%}",format(win_B,win_B/number_of_games))
def main():
    #主要逻辑
    proh_A, proh_B,number_of_games = get_inputs()
    win_A,win_B = sim_n_games(proh_A, proh_B,number_of_games)
    print_summer(win_A, win_B, number_of_games)
main()