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题目
给你两个字符串数组 word1 和 word2 。如果两个数组表示的字符串相同，返回 true ；否则，返回 false 。
数组表示的字符串 是由数组中的所有元素 按顺序 连接形成的字符串。
示例 1： 输入：word1 = ["ab", "c"], word2 = ["a", "bc"] 输出：true 解释： word1 表示的字符串为 "ab" + "c" -> "abc" word2 表示的字符串为 "a" + "bc" -> "abc" 两个字符串相同，返回 true 示例 2： 输入：word1 = ["a", "cb"], word2 = ["ab", "c"] 输出：false 示例 3： 输入：word1 = ["abc", "d", "defg"], word2 = ["abcddefg"] 输出：true
提示：
1 <= word1.length, word2.length <= 103 1 <= word1[i].length, word2[i].length <= 103 1 <= sum(word1[i].length), sum(word2[i].length) <= 103 word1[i] 和 word2[i] 由小写字母组成
解题思路
class Solution: def arrayStringsAreEqual(self, word1: List[str], word2: List[str]) -> bool: # 用join，把list转成str word1Str = "".join(word1) word2Str = "".join(word2) return word1Str == word2Str if __name__ == '__main__': word1 = ["ab", "c"] word2 = ["a", "bc"] word1 = ["a", "cb"] word2 = ["ab", "c"] ret = Solution().arrayStringsAreEqual(word1, word2) print(ret)
