题目内容
无线电台的RS制信号报告是由三两个部分组成的：
R(Readability) 信号可辨度即清晰度.
S(Strength) 信号强度即大小.
其中R位于报告第一位，共分5级，用1—5数字表示.
1—Unreadable
2—Barely readable, occasional words distinguishable
3—Readable with considerable difficulty
4—Readable with practically no difficulty
5—Perfectly readable
报告第二位是S，共分九个级别，用1—9中的一位数字表示
1—Faint signals, barely perceptible
2—Very weak signals
3—Weak signals
4—Fair signals
5—Fairly good signals
6—Good signals
7—Moderately strong signals
8—Strong signals
9—Extremely strong signals
现在，你的程序要读入一个信号报告的数字，然后输出对应的含义。如读到59，则输出：
Extremely strong signals, perfectly readable.
代码展示
import java.util.Scanner; public class RS { public static void main(String[] args) { System.out.print("输入RS值："); Scanner intrs = new Scanner(System.in); int rs = intrs.nextInt(); int r = rs/10; int s = rs-10*r; // System.out.println(r+","+s); // 判断s输出的结果 switch (s) { case 1: System.out.print("Faint signals, barely perceptible"); break; case 2: System.out.print("Very weak signals"); break; case 3: System.out.print("Weak signals"); break; case 4: System.out.print("Fair signals"); break; case 5: System.out.print("Fairly good signals"); break; case 6: System.out.print("Good signals"); break; case 7: System.out.print("Moderately strong signals"); break; case 8: System.out.print("Strong signals"); break; case 9: System.out.print("Extremely strong signals"); break; } // 中间分隔的， System.out.print(", "); //判断r switch (r) { case 1: System.out.print("unreadable"); break; case 2: System.out.print("barely readable, occasional words distinguishable"); break; case 3: System.out.print("readable with considerable difficulty"); break; case 4: System.out.print("readable with practically no difficulty"); break; case 5: System.out.print("perfectly readable"); break; } // 最后输出的。 System.out.println("."); // 清理缓存 intrs.close(); } }
结果查看
踩坑指南
这里的坑比较少，首先就是可以添加一个判断输入数据是否正确，然后在使用的时候选择了switch语句这样子代码量相对少一些，如果是if就会出现大量的{}没有太大的必要。
