有关一百以内数字的Python算法

for i in range(1,101):
    print(i,end = ' ')

sumNumber = 0
for i in range(1,101):
  sumNumber += i
print('1~100之间所有数字之和是：',sumNumber)
print('1~100之间所有数字之和是：',sum(range(1,101)))
输出1~100之间所有奇数
numbers = []
for i in range(1,101):
  if (i % 2) == 1:
  numbers.append(i)
print(numbers)

numbers = []
for i in range(1,101):
  if (i % 2) == 0:
  numbers.append(i)
print(numbers)

def prime(maxNumber):
    numbers = []
    min = 2
    while min <= maxNumber:
        is_prime = True
        for i in range(2,min):
            if (min % i) == 0:
                is_prime = False
                break
        if is_prime == True:
            numbers.append(min)
        min += 1
    print('{0} 以内的质数有：'.format(maxNumber))
    print(numbers)
    print()
prime(100)

# coding : utf-8
def prime(maxNumber):
    numbers = []
    min = 2
    numberSum = 0
    while min <= maxNumber:
        is_prime = True
        for i in range(2,min):
            if (min % i) == 0:
                is_prime = False
                break
        if is_prime == True:
            numbers.append(min)
        min += 1
    for i in numbers:
        numberSum += i
    print('%s以内的质数和是：%s' % (maxNumber,numberSum))
prime(100)

maxNumber = 100
numbers = []
min = 2
numberSum = 0
for i in range(1,101):
    numbers.append(i)
while min <= maxNumber:
    is_prime = True
    for i in range(2,min):
        if (min % i) == 0:
            is_prime = False
            break
    if is_prime == True:
        numbers.remove(min)
    min += 1
print(numbers)

from math import pi
from math import e
print('圆周率：',pi)
print('自然常数：',e)