解题思路
此题的步骤
- 定义一个哈希字典，计算每个元素个数
- 以
value的大小，对字典进行重排序 - 解析成字符串形式
代码
class Solution: def frequencySort(self, s: str) -> str: Hash = {i:0 for i in set(s)} for i in s: Hash["%s"%i] += 1 dict= sorted(Hash.items(), key=lambda d:d[1], reverse = True) str1 = "" for character,num in dict: str1 += character * num return str1
