文章目录
- AcWing 714. 连续奇数的和 1
- AC代码
AcWing 714. 连续奇数的和 1
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AC代码
代码:
#include <iostream> using namespace std; int main() { int x, y, sum = 0; cin >> x >> y; if (y < x) { int t = x; x = y; y = t; } int len = y - x + 1; for (int i = 1; i < len - 1; i ++ ) if ((i + x) % 2 == 1 || (i + x) % 2 == -1) sum = sum + i + x; cout << sum; return 0; }