201509-2 日期计算

#include <iostream>
using namespace std;
int months[13] = {
    0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31
};
int is_leap(int year)
{
    if (year % 4 == 0 && year % 100 || year % 400 == 0)
        return 1;
    return 0;
}
int get_days(int y, int m)
{
    int s = months[m];
    if (m == 2) return s + is_leap(y);
    return s;
}
int main()
{
    int year, d;
    cin >> year >> d;
    for (int i = 1; i <= 12; i ++ )
        for (int j = 1; j <= get_days(year, i); j ++ )
        {
            if ( -- d == 0)
            {
                printf("%d\n%d\n", i, j);
                return 0;
            }
        }
    return 0;
}