Lombda 表达式，使用多线程，如何使用 wait 释放线程资源。?报错

                    <pre>

import java.util.concurrent.atomic.AtomicInteger; import java.util.concurrent.locks.Condition; import java.util.concurrent.locks.Lock; import java.util.concurrent.locks.ReentrantLock;

public class DemoMain {

public static void main(String[] args) {
    DemoMain demo = new DemoMain();
    demo.market();
}

public void market(){
    AtomicInteger bread = new AtomicInteger(0);
    Lock lock = new ReentrantLock();
    Condition condition = lock.newCondition();

    Runnable product = () -> {
        while (true) {
            try {
                lock.lock();
                if (bread.get() < 99) {
                    bread.getAndIncrement();
                }else{
                    condition.await();
                }
                System.out.println("生产者生产后，还有 " + bread.get() + " 个面包");
            } catch (Exception e) {
                e.printStackTrace();
            } finally {
                condition.signal();
                lock.unlock();
            }
        }
    };

    Runnable consumer = () -> {
        while (true) {
            try {
                lock.lock();
                if (bread.get() >= 1) {
                    bread.addAndGet(-1);
                }else{
                    condition.await();
                }
                System.out.println("消费者消费后，还有 " + bread.get() + " 个面包");
            } catch (Exception e) {
                e.printStackTrace();
            } finally {
                condition.signal();
                lock.unlock();
            }
        }
    };

    new Thread(product).start();
    new Thread(consumer).start();
}

}

https://blog.csdn.net/wd_888/article/details/105154184