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阿里云sdk 返回的数据php怎么处理?

{"data":{"total":1,"list":[{"id":390,"gmtCreate":null,"gmtModified":null,"userId":582,"isvName":"内蒙古烽泰科技有限公司","userName":"奇力格尔","farmName":"奇力格尔牧场","farmType":null,"farmTypeName":null,"cityCode":150600,"cityName":"鄂尔多斯市","areaCode":150624,"areaName":"鄂托克旗","latlon":"107.971574,39.458733","address":"阿尔巴斯苏木乌兰其日嘎嘎查","telephone":"15847316516","linkman":"奇力格尔","farmDescribe":"","farmState":null,"farmStateName":null,"houseProperty":null,"housePropertyName":null,"buildDate":null,"houseArea":null,"scale":330,"farmYear":null,"sourceWater":null,"sourceWaterName":null,"structure":null,"structureName":null,"traffic":null,"trafficName":null,"ventilation":null,"ventilationName":null,"houseNumber":null,"sewageDisposal":null,"sewageDisposalName":null,"green":null,"greenName":null,"cool":null,"coolName":null,"state":null,"stateName":null,"cardVersion":null,"columnsNum":null,"bedsNum":null,"buildCategory":null,"remarks":null,"provinceCode":150000,"provinceName":"内蒙古自治区","isvId":9}],"pageNum":1,"pageSize":10,"size":1,"startRow":1,"endRow":1,"pages":1,"prePage":0,"nextPage":0,"isFirstPage":true,"isLastPage":true,"hasPreviousPage":false,"hasNextPage":false,"navigatePages":8,"navigatepageNums":[1],"navigateFirstPage":1,"navigateLastPage":1},"errCode":0,"errMsg":"正常","requestId":"863615ea-f312-47c9-83a3-8241ac425399"}HttpResponse
Object
(
[content:HttpResponse:private] => 1
[body:HttpResponse:private] =>
[header:HttpResponse:private] => 1
[requestId:HttpResponse:private] =>
[errorMessage:HttpResponse:private] =>
[contentType:HttpResponse:private] => application/json; charset=UTF-8
[httpStatusCode:HttpResponse:private] => 200
)

怎么过滤掉:HttpResponse Object

遇到了同样的问题,在CSDN看到了,希望阿里云团队能够给出正确、标准的答案~请查看

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西门小刚刚9630297551 2020-05-22 21:20:15 1116 分享 版权
阿里云 AI 助理回答

从您提供的信息来看,您似乎是在处理API响应数据时遇到了包含“HttpResponse Object”字样的输出,这可能是由于在打印或处理HTTP响应对象时直接将整个对象(包括其内部属性和结构)输出到了控制台或日志中。如果您希望仅获取并处理JSON格式的数据部分,可以按照以下步骤操作:

使用PHP示例

假设您使用的是PHP语言来处理这个API响应,您可以这样过滤掉不需要的HttpResponse对象信息,并只保留JSON数据内容:

// 假设$response是您的HttpResponse对象
$jsonContent = json_encode($response->getBody()); // 获取响应体内容并转换为JSON字符串

// 解码JSON字符串为数组,以便进一步处理
$data = json_decode($jsonContent, true);

// 现在"data"数组包含了您需要的信息
echo json_encode($data, JSON_PRETTY_PRINT); // 以美化的方式打印出JSON数据

这段代码首先通过$response->getBody()获取到HTTP响应的内容,然后将其编码为JSON字符串。接着,使用json_decode函数将JSON字符串解码为PHP数组,这样就可以方便地访问和操作数据了。

注意事项

  • 上述示例基于您能够直接访问到响应对象的getBody方法或其他类似方法来获取原始响应内容。不同的库或框架可能有不同的方法来访问响应体。
  • 确保您的环境已经正确设置了HTTP客户端库(如GuzzleHttp等),并且您有权访问和操作响应对象。
  • 如果您的实际场景中不直接操作HttpResponse对象,而是接收到的是一个字符串形式的响应内容,那么直接对字符串进行JSON解码即可。

请根据您实际使用的编程语言和库的具体API调整上述代码示例。

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