将Exception传递给自定义的Exception Handler方法

我有一个带有大约20个方法的类，这些方法都捕获1个或多个异常，然后根据该异常响应用户。我不想创建一遍又一遍的方法，而是要创建一个方法，该方法将传递给Exception，对其进行处理并给出适当的响应。

这是一个例子

public boolean addFirst(Object data){

    try {
        //add something 
        return true;
    } catch(Exception e) {
        exceptionHandler(e);
        return false;
    } 
}

但是，当我尝试将其与“ e”进行比较时，它给了我“ 无法将异常解析为变量”。

private void exceptionHandler(Exception e) {
    if(e == UnsupportedOperationException) {
        System.out.println("Operation is not supported.");
    } else if (e == ClassCastException) {
        System.out.println("Class of the specified element prevents it from being added to this list.");
    } else if (e == NullPointerException) {
        System.out.println("You cannot enter nothing.");
    } else if (e == IndexOutOfBoundsException) {
        System.out.println("Your specified index is larger than the size of the LinkedList. Please choose a lower value.");
    } else if(e == Exception) {
        System.out.println("You messed up so hard that I don't even know what you did wrong."); 
    }
}

问题来源：Stack Overflow