同时遍历两个数组

使用Swift 5，您可以使用以下4种Playground代码之一来解决您的问题。

＃1 使用zip(::)功能 在最简单的情况下，您可以zip(::)用来创建初始数组中元素对的新序列（元组）。

let strArr1 = ["Some1", "Some2", "Some3"] let strArr2 = ["Somethingelse1", "Somethingelse2"]

let sequence = zip(strArr1, strArr2)

for (el1, el2) in sequence { print("(el1) - (el2)") }

/* prints: Some1 - Somethingelse1 Some2 - Somethingelse2 */ ＃2。使用Array的makeIterator()方法和while循环 使用简单的while循环和迭代器同时循环两个数组也很容易：

let strArr1 = ["Some1", "Some2", "Some3"] let strArr2 = ["Somethingelse1", "Somethingelse2"]

var iter1 = strArr1.makeIterator() var iter2 = strArr2.makeIterator()

while let el1 = iter1.next(), let el2 = iter2.next() { print("(el1) - (el2)") }

/* prints: Some1 - Somethingelse1 Some2 - Somethingelse2 */ ＃3。使用符合以下条件的自定义类型IteratorProtocol 在某些情况下，您可能需要创建自己的类型，以将姓名缩写数组的元素配对。可以通过使您的类型符合来实现IteratorProtocol。请注意，通过使您的类型也符合Sequence协议，您可以在for循环中直接使用其实例：

struct TupleIterator: Sequence, IteratorProtocol {

private var firstIterator: IndexingIterator<[String]>
private var secondIterator: IndexingIterator<[String]>

init(firstArray: [String], secondArray: [String]) {
    self.firstIterator = firstArray.makeIterator()
    self.secondIterator = secondArray.makeIterator()
}

mutating func next() -> (String, String)? {
    guard let el1 = firstIterator.next(), let el2 = secondIterator.next() else { return nil }
    return (el1, el2)
}

}

let strArr1 = ["Some1", "Some2", "Some3"] let strArr2 = ["Somethingelse1", "Somethingelse2"]

let tupleSequence = TupleIterator(firstArray: strArr1, secondArray: strArr2)

for (el1, el2) in tupleSequence { print("(el1) - (el2)") }

/* prints: Some1 - Somethingelse1 Some2 - Somethingelse2 */ ＃4。使用AnyIterator 作为上一个示例的替代方法，您可以使用AnyIterator。以下代码显示了在Array扩展方法中可能的实现：

extension Array {

func pairWithElements(of array: Array) -> AnyIterator<(Element, Element)> {
    var iter1 = self.makeIterator()
    var iter2 = array.makeIterator()

    return AnyIterator({
        guard let el1 = iter1.next(), let el2 = iter2.next() else { return nil }
        return (el1, el2)
    })
}

}

let strArr1 = ["Some1", "Some2", "Some3"] let strArr2 = ["Somethingelse1", "Somethingelse2"]

let iterator = strArr1.pairWithElements(of: strArr2)

for (el1, el2) in iterator { print("(el1) - (el2)") }

/* prints: Some1 - Somethingelse1 Some2 - Somethingelse2 */