SQL Server中的时间范围仅适用于日期
我有一个名为Name的表Transactions，它包含这样的数据：
transaction_id cust_id tran_date
80712190438 270351 28-02-14
29258453508 270384 27-02-14
58387181112 275068 31-12-13
21300411973 274568 31-12-13
26229626485 267624 31-12-12
26229126485 267634 31-12-12
47557596721 273764 31-12-11
28966519600 273899 31-12-11
现在，可用于分析的交易数据的时间范围是多少？
问题的第二部分是：
显示在输出number of Days，Months并Years同时进行。
两者都应在“单个查询”中完成。
我使用下面的查询来获取天，月和年，但是我一直在寻找时间范围。
SELECT
MIN(CAST(CAST(tran_date AS NCHAR(8)) AS date)) AS Start_tran_Date
,MAX(CAST(CAST(tran_date AS NCHAR(8)) AS date)) AS End_tran_Date
,DATEDIFF(DAY,MAX(CAST(CAST(tran_date AS NCHAR(8)) AS date)), MIN(CAST(CAST(tran_date AS NCHAR(8)) AS date)) ) AS Difference_Days
,DATEDIFF(MONTH,MAX(CAST(CAST(tran_date AS NCHAR(8)) AS date)), MIN(CAST(CAST(tran_date AS NCHAR(8)) AS date)) ) AS Difference_Months
,DATEDIFF(YEAR,MAX(CAST(CAST(tran_date AS NCHAR(8)) AS date)), MIN(CAST(CAST(tran_date AS NCHAR(8)) AS date)) ) AS Difference_Years
FROM Transactions
但这给了我这个错误：
消息241，级别16，状态1，第50行从字符串转换日期和/或时间时转换失败。
我想要输出
tran_date_start tran_date_end No.of Days No.of Months No.of Years
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在Anoymous的答案上，您可以使用子查询使代码更清晰-像这样：
SELECT MIN(trans_dt) AS Start_tran_Date, MAX(trans_dt) AS End_tran_Date, DATEDIFF(DAY, MAX(trans_dt), MIN(trans_dt) ) AS Difference_Days, DATEDIFF(MONTH,MAX(trans_dt), MIN(trans_dt) ) AS Difference_Months, DATEDIFF(YEAR, MAX(trans_dt), MIN(trans_dt) ) AS Difference_Years FROM ( SELECT transaction_id, cust_id, CONVERT(date,tran_date,3) as tran_dt FROM Transaction )2020-01-03 16:35:34赞同 展开评论
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