使用strcopy时崩溃

我正在尝试解决以下问题：从用户读取X行文本，每个行的最大Y个字符长。（X和Y是常量。）删除换行符，并且不要使数组的长度超过所需的长度。完成后，请确保所有内容均免费提供。使用fgets并使用另一种方法读取一行和读取X行。这是我的尝试。它在strcpy的方法“ read_multiple”中崩溃，但是我不确定为什么。很抱歉，这又是一件容易的事，但是我被困了几个小时才敢承认。

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

#define AMOUNT 5 //max AMOUNT of chars in one line
#define MAXAMOUNT 3 //max AMOUNT of lines that will be read

char* read();

char** read_multiple();

void write(char**);

void clean(char**);

int main()
{
    char** arr = read_multiple();
    write(arr);
    clean(arr);
    return 0;
}
char** read_multiple()
{
    char* arr[MAXAMOUNT + 1];
    char* word;
    int i = 0, not_stop = 1, x = 0;
    while (i < MAXAMOUNT && not_stop) {
        word = read();
        not_stop = strcmp(word, "STOP");
        if (not_stop) {
            arr[i] = word;
            i++;
        }
    }
    //create space on heap
    char** res = (char**)malloc((i + 1) * sizeof(char*));
    //copy everything to res from [0,i[
    for (x = 0; x < i; x++) {
        printf("->%s\n", arr[x]);
        strcpy(res[x], arr[x]);
    }
    res[i] = NULL;
    //write(res);
    return res;
}
void write(char** arr)
{
    puts("Array: ");
    while (*arr) {
        puts(*arr);
        arr++;
    }
}

char* read()
{
    int length;
    char c;
    char word[AMOUNT + 1]; //last char will be occipied by '\0'!
    printf("Enter a sentence of %d characters:\n", AMOUNT);
    fgets(word, AMOUNT + 1, stdin);

    //remove '\n'
    char* p = word;
    while (*p && *p != '\n')
        p++;
    *p = '\0';

    //clear input buffer if necessary
    length = strlen(word);
    if (length == AMOUNT)
        while (c != '\n' && c != EOF)
            c = getchar();

    //reserve space on heap and return pointer
    char* res = (char*)malloc(length * sizeof(char));
    strcpy(res, word);
    return res;
}

void clean(char** arr)
{
    while (*arr) {
        printf("Free:%s\n", *arr);
        free(*arr);
        arr++;
    }
    free(arr);
}