如何格式化一个美丽的汤的整个输出(列表)?
我试图格式的全部输出我美丽的汤网页刮刀在这里。输出如下:
AT-FVFX1BN7J1WK:Python 522672$ /Library/Frameworks/Python.framework/Versions/3.7/bin/python3 "/Users/522672/Desktop/Python/Scraper/Beautiful Soup/Python2.py"
[<div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="@-yet">@-yet</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="ADDI-DATA">ADDI-DATA</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="ADE-Werk">ADE-Werk</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="Adelmann Umwelt">Adelmann Umwelt</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="Ademco 1">Ademco 1</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="adesso">adesso</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="ADITO Software">ADITO Software</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="ADMOS Gleitlager">ADMOS Gleitlager</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="ads-tec Industrial IT">ads-tec Industrial IT</div>
</div>, <div class="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left">
<div class="ellipsis" title="ADVES">ADVES</div>
</div>]
这是我在打印company_name时得到的原始输出，但是我不知道如何将company_name格式化为只有公司名称。所以当我打印company_name时，我只会得到一个完整的公司列表，就像“@-yet”或“ADDI-ADTA”那样。
from bs4 import BeautifulSoup
import requests
import lxml
url = 'https://www.vdma.org/en/mitglieder?p_p_lifecycle=2&p_p_resource_id=getPage&p_p_id=vdma2publicusers_WAR_vdma2publicusers&s=&page=5'
page = requests.get(url)
soup = BeautifulSoup(page.content, 'html.parser')
company_name = soup.find_all('div', class_="col-xs-7 col-sm-7 col-md-7 col-lg-7 text-left")
company_website = soup.find_all('div', class_="col-xs-5 col-sm-5 col-md-5 col-lg-5 text-right")
company_adress = soup.find_all('div', class_="col-xs-5 col-sm-5 col-md-5 col-lg-5")
company_contact = soup.find_all('div', class_="col-xs-10 col-sm-10 col-md-9 col-lg-9")
问题来源StackOverflow 地址：/questions/59383246/how-to-format-an-entire-output-list-of-a-beautiful-soup
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尝试使用这个CSS选择器来获得公司名称 更新后的代码:
from bs4 import BeautifulSoup import requests url = 'https://www.vdma.org/en/mitglieder?p_p_lifecycle=2&p_p_resource_id=getPage&p_p_id=vdma2publicusers_WAR_vdma2publicusers&s=&page=5' page = requests.get(url) soup = BeautifulSoup(page.content, 'html.parser') with open ("test.txt", "w") as output: companies = soup.select('.col-lg-10') for company in companies: company_name = company.select('.text-left')[0].text.strip() company_contacts = company.select('.col-lg-9 .ellipsis') # If you want to check the type of every contact # for contact in company_contacts: # if "@" in contact.text.strip(): # print("Contact is email") # else: # print("Contact is a number") output.write(f"Name: {company_name}\nContacts: {', '.join([contact.text.strip() for contact in company_contacts])}\n\n") # Output # Name: 2W Technische Informations # Contacts: info@2wgmbh.de, (+49 89) 5 20 35-0 # Name: 3 S Schnecken + Spindeln + Spiralen # Contacts: office@3s-gmbh.at, (+43 7613) 50 04 # Name: 365FarmNet # Contacts: info@365farmnet.com, (+49 30) 2 59 32 95 00, (+49 30) 2 59 32 95 01 # Name: 3D Interaction Technologies # Contacts: info@3dit.de, (+49 351) 21 96-74 95 # ...2019-12-27 10:33:15赞同 展开评论 打赏
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