我的python石头剪刀布游戏怎么了?一切都错了吗?

import random

def result(num): if num == 1: ret = '石头' elif num == 2: ret = '剪刀' else: ret = '布' return ret

def games(nums): for i in range(nums): try: # 得到键盘内容 player_num = input('请输入 [ 1. 石头 2. 剪刀 3. 布] 退出请输入 exit ') # 如果键盘输入的是exit, 就直接跳出当前循环, 结束程序 if player_num == 'exit': break

        # 判断用户输入的内容是不是字符串类型的 1 2 3 如果不是, 则主动抛出异常
        if player_num not in ['1', '2', '3']:
            raise 123

        # 用于把数字和石头剪刀布对应起来, 待会下面输入就能够很好的字符串拼接
        you = result(int(player_num))

        # 把用户输入的内容转换成数字类型, 能够走到这里, 就代码player_num决定是字符串类型的 1 2 3
        player_num = int(player_num)

    except Exception:
        print('输入有误, 请重新来过')
        continue

    # 电脑出拳
    computer_num = random.randint(1, 3)
    # 用于把数字和石头剪刀布对应起来, 待会下面电脑输入就能够很好的字符串拼接
    computer = result(computer_num)

    if (player_num == 1 and computer_num == 2) or (player_num == 2 and computer_num == 3) or (
            player_num == 3 and computer_num == 1):
        print('')
        print('*' * 50)
        print('你出的是%s' % you)
        print('电脑出的是%s' % computer)
        print('你赢了, 你向对方说, 不要跑, 决战到天亮!!')
        print('*' * 50)
        print('')

    elif player_num == computer_num:
        print('')
        print('*' * 50)
        print('你出的是%s' % you)
        print('电脑出的是%s' % computer)
        print('打平了')
        print('*' * 50)
        print('')

    else:
        print('')
        print('*' * 50)
        print('你出的是%s' % you)
        print('电脑出的是%s' % computer)
        print('你输了, 但是不要气馁, 再接再励!')
        print('*' * 50)
        print('')

if name == 'main': print("欢迎来到猜拳游戏*") nums = int(input('请问你想玩几盘: ')) print("游戏开始*") games(nums)