下面是删除链接的简单列表的最后一个节点的完整代码,如果工作良好,该函数将无效deleteLastNode()。
但是这部分到底是什么意思?在我看来,这是多余的,因为当while循环结束时,我们将toDelete节点放在最后,将secondLastNode作为倒数第二个。
if(toDelete == head)
{
head = NULL;
}
deleteLastNode()函数是这样的:
void deleteLastNode()
{
struct node *toDelete, *secondLastNode;
if(head == NULL)
{
printf("List is already empty.");
}
else
{
toDelete = head;
secondLastNode = head;
/* Traverse to the last node of the list */
while(toDelete->next != NULL)
{
secondLastNode = toDelete;
toDelete = toDelete->next;
}
if(toDelete == head)
{
head = NULL;
}
else
{
/* Disconnect link of second last node with last node */
secondLastNode->next = NULL;
}
/* Delete the last node */
free(toDelete);
printf("SUCCESSFULLY DELETED LAST NODE OF LIST\n");
}
}
但我相信这是足够的:
/* */
void deleteLastNode()
{
struct node *toDelete, *secondLastNode;
if(head == NULL)
{
printf("List is already empty.");
}
else
{
toDelete = head;
secondLastNode = head;
/* Traverse to the last node of the list */
while(toDelete->next != NULL)
{
secondLastNode = toDelete;
toDelete = toDelete->next;
}
/* Disconnect link of second last node with last node */
secondLastNode->next = NULL;
/* Delete the last node */
free(toDelete);
printf("SUCCESSFULLY DELETED LAST NODE OF LIST\n");
}
}
完整的代码是这样的:并且函数无效deleteLastNode()::
/**
* C program to delete last node of Singly Linked List
*/
#include <stdio.h>
#include <stdlib.h>
/* Structure of a node */
struct node {
int data; // Data
struct node *next; // Address
}*head;
void createList(int n);
void deleteLastNode();
void displayList();
int main()
{
int n, choice;
/*
* Create a singly linked list of n nodes
*/
printf("Enter the total number of nodes: ");
scanf("%d", &n);
createList(n);
printf("\nData in the list \n");
displayList();
printf("\nPress 1 to delete last node: ");
scanf("%d", &choice);
/* Delete last node from list */
if(choice == 1)
deleteLastNode();
printf("\nData in the list \n");
displayList();
return 0;
}
/*
* Create a list of n nodes
*/
void createList(int n)
{
struct node *newNode, *temp;
int data, i;
head = (struct node *)malloc(sizeof(struct node));
/*
* If unable to allocate memory for head node
*/
if(head == NULL)
{
printf("Unable to allocate memory.");
}
else
{
/*
* Input data of node from the user
*/
printf("Enter the data of node 1: ");
scanf("%d", &data);
head->data = data; // Link the data field with data
head->next = NULL; // Link the address field to NULL
temp = head;
/*
* Create n nodes and adds to linked list
*/
for(i=2; i<=n; i++)
{
newNode = (struct node *)malloc(sizeof(struct node));
/* If memory is not allocated for newNode */
if(newNode == NULL)
{
printf("Unable to allocate memory.");
break;
}
else
{
printf("Enter the data of node %d: ", i);
scanf("%d", &data);
newNode->data = data; // Link the data field of newNode with data
newNode->next = NULL; // Link the address field of newNode with NULL
temp->next = newNode; // Link previous node i.e. temp to the newNode
temp = temp->next;
}
}
printf("SINGLY LINKED LIST CREATED SUCCESSFULLY\n");
}
}
/*
* Delete last node of the linked list
*/
void deleteLastNode()
{
struct node *toDelete, *secondLastNode;
if(head == NULL)
{
printf("List is already empty.");
}
else
{
toDelete = head;
secondLastNode = head;
/* Traverse to the last node of the list */
while(toDelete->next != NULL)
{
secondLastNode = toDelete;
toDelete = toDelete->next;
}
if(toDelete == head)
{
head = NULL;
}
else
{
/* Disconnect link of second last node with last node */
secondLastNode->next = NULL;
}
/* Delete the last node */
free(toDelete);
printf("SUCCESSFULLY DELETED LAST NODE OF LIST\n");
}
}
/*
* Display entire list
*/
void displayList()
{
struct node *temp;
/*
* If the list is empty i.e. head = NULL
*/
if(head == NULL)
{
printf("List is empty.");
}
else
{
temp = head;
while(temp != NULL)
{
printf("Data = %d\n", temp->data); // Print the data of current node
temp = temp->next; // Move to next node
}
}
}
在第二个函数实现中,如果最后一个节点是头节点,则变量头本身不会更改。因此,当列表仅包含一个作为头节点的节点时,该函数可能具有未定义的行为。
请注意,在任何情况下,函数实现都是错误的。例如,该函数处理全局变量head。因此,在一个程序内您不能定义两个列表。
该函数可以编写得更简单。
void deleteLastNode( struct node **head )
{
if ( *head != NULL )
{
while ( ( *head )->next != NULL ) head = &( *head )->next;
free( *head );
*head = NULL;
}
}
叫像
deleteLastNode( &head );
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