387. First Unique Character in a String
Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.
Examples:
s = "leetcode" return 0. s = "loveleetcode", return 2.
Note: You may assume the string contain only lowercase letters.
此题比较简单
代码如下:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
|
class
Solution {
public
:
int
firstUniqChar(string s) {
set<
char
> myset;
if
(s.empty())
{
return
-1;
}
for
(
int
i = 0 ; i < s.size();i++)
{
char
c = s[i];
int
j;
if
(myset.find(c) != myset.end())
{
continue
;
}
for
(j = i + 1; j < s.size();j++)
{
if
(s[j] == s[i])
{
myset.insert(c);
break
;
}
}
if
(j == s.size() )
{
return
i;
}
}
return
-1;
}
};
|
本文转自313119992 51CTO博客,原文链接:http://blog.51cto.com/qiaopeng688/1842229