对List内元素进行全排列

对List中元素进行全排列，使用了递归，代码如下：

class Program

    {

        static void  Main (string[] args)

        {

            List<int> list = new List<int>() { 6,7,8};

            foreach (var p 1  in  Permutate(list, list.Count))

            {

                foreach (var i in p1)

                    Console.Write(i.ToString() + " ");

                Console.WriteLine();

            }

            string strTest = " Cary ";

            foreach (List<char> p 2  in  Permutate(strTest.ToCharArray().ToList(), strTest.Length))

            {

                string strTmp = new string(p2.ToArray());

                Console.Write(strTmp + "\t");

            }

            Console.WriteLine();

        }

        public static void CircleRight(IList seq, int count)

        {

            object tmp = seq[count - 1];

            seq.RemoveAt(count - 1);

            seq.Insert(0, tmp);

        }

        public static IEnumerable<IList> Permutate(IList seq, int count)

        {

            if (count == 1) yield return seq;

            else

            {

                for (int i = 0; i < count; i++)

                {

                    foreach (var perm in Permutate(seq, count - 1))

                        yield return perm;

                    CircleRight(seq, count);

                }

            }

        }      

}

结果如下：

本文转自生鱼片博客园博客，原文链接：http://www.cnblogs.com/carysun/archive/2009/11/16/List-Permutate.html，如需转载请自行联系原作者