[Papers]NSE, $u$, Lorentz space [Bjorland-Vasseur, JMFM, 2011]

简介: $$\bex \int_0^T\frac{\sen{\bbu}_{L^{q,\infty}}^p}{\ve+\ln \sex{e+\sen{\bbu}_{L^\infty}}}\rd s

$$\bex \int_0^T\frac{\sen{\bbu}_{L^{q,\infty}}^p}{\ve+\ln \sex{e+\sen{\bbu}_{L^\infty}}}\rd s<\infty. \eex$$

目录
相关文章
|
算法
light oj 1258 - Making Huge Palindromes(KMP)
ight oj里这个题目是属于KMP分类的,但乍看好像不是kmp,因为只有一个字符串。要想的到一个回文串,把该字符串翻转接到原串后面必然是一个回文串,但并不一定是最短的。我们必须考虑怎么把两个串尽量融合在一起,这就要看翻转串的前段与原串的后段有多少是匹配的了,这里就用到了KMP算法。
46 1
|
机器学习/深度学习 算法框架/工具 TensorFlow
(转) AdversarialNetsPapers
  本文转自:https://github.com/zhangqianhui/AdversarialNetsPapers AdversarialNetsPapers The classical Papers about adversarial nets The First pap...
[Papers]NSE, $u$, Lorentz space [Bosia-Pata-Robinson, JMFM, 2014]
$$\bex \bbu\in L^p(0,T;L^{q,\infty}),\quad \frac{2}{p}+\frac{3}{q}=1,\quad 3
800 0
[Papers]NSE, $u$, Lorentz space [Sohr, JEE, 2001]
$$\bex \bbu\in L^{p,r}(0,T;L^{q,\infty}(\bbR^3)),\quad\frac{2}{p}+\frac{3}{q}=1,\quad 3
1056 0
|
Python
[Papers]NSE, $\pi$, Lorentz space [Suzuki, JMFM, 2012]
$$\bex \sen{\pi}_{L^{s,\infty}(0,T;L^{q,\infty}(\bbR^3))} \leq \ve_*, \eex$$ with $$\bex \frac{2}{s}+\frac{3}{q}=2,\quad \frac{5}{2}\leq q\leq 3.
663 0
[Papers]NSE, $\p_3u$, multiplier spaces [Guo-Gala, ANAP, 2013]
$$\bex \p_3\bbu\in L^\frac{2}{1-r}(0,T;\dot X_r(\bbR^3)),\quad 0\leq r\leq 1. \eex$$
704 0
[Papers]NSE, $u_3$, Lebesgue space [Jia-Zhou, NARWA, 2014]
$$\bex u_3\in L^\infty(0,T;L^\frac{10}{3}(\bbR^3)). \eex$$
737 0
[Papers]NSE, $u_3$, Lebesgue space [Kukavica-Ziane, Nonlinearity, 2006]
$$\bex u_3\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=\frac{5}{8},\quad \frac{24}{5}
746 0
[Papers]NSE, $\p_3u$, Lebesgue space [Cao, DCDSA, 2010]
$$\bex \p_3\bbu\in L^p(0,T;L^q(\bbR^3)),\quad \frac{2}{p}+\frac{3}{q}=2,\quad \frac{27}{16}\leq q\leq \frac{5}{2}. \eex$$
782 0