对时间字符串进行比较和处理
判断当前输入的时间必须是大于当天的23:59:59的:
String dateTime = "2017-12-13 15:50:23"//界面输入时间 SimpleDateFormat myFormat = new SimpleDateFormat("yyyy-MM-dd 23:59:59") Calendar calendar = Calendar.getInstance() String mystrdate = myFormat.format(calendar.getTime()) //当天时间精确到23:59:59 SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss") Date beginDate = sdf.parse(dateTime) Date endDate = sdf.parse(mystrdate) if(endDate.time-beginDate.time>=0){ print("11111") }else{ print("22222") }
获取当前系统时间：
SimpleDateFormat myFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss") Calendar calendar = Calendar.getInstance() String mystrdate = myFormat.format(calendar.getTime()) print(mystrdate)
判断时间为多久之前进行相关页面的返回：
static String simpleRangeTimes(Long time) { Long cTime = getTime().time - time if (cTime > 0 && cTime < 600000l) return "刚刚" //0分钟＜X＜10分钟 if (cTime > 600000l && cTime < 3600000l) return "1小时前"//10分钟≤X＜60分钟，显示“1小时前” if (cTime > 3600000l && cTime < 7200000l) return "2小时前"//60分钟≤X＜120分钟，显示“2小时前” else return formatDate(time, "yyyy-MM-dd") }
或者另外一种方式
/** * 和当前时间比较，简洁显示 * 1小时之前，显示到分钟；24小时之前显示到小时；1个月前显示到天 * @param time * @return */ static String simpleRangeTime(Long time) { Long cTime = getTime().time - time if (cTime < 60000l) return "刚刚" if (cTime < 3600000l) return (cTime / (1000 * 60) as int) + "分钟前" if (cTime < 86400000l) return (cTime / (1000 * 60 * 60) as int) + "小时前" if (cTime < 2592000000l) return (cTime / (1000 * 60 * 60 * 24) as int) + "天前" else return "很久以前" }
使用时间计算年龄:
/** * 计算年龄 * @param birthday * @return */ static int getAge(long birthday) { Calendar born = Calendar.getInstance(); Calendar now = Calendar.getInstance(); born.setTimeInMillis(birthday) now.setTimeInMillis(new Date().getTime()) def age = now.get(Calendar.YEAR) - born.get(Calendar.YEAR) if (now.get(Calendar.DAY_OF_YEAR) < born.get(Calendar.DAY_OF_YEAR)) { age -= 1; } return age } /** * 计算年龄 * @param birthday , 格式yyyy-MM-dd * @return */ static int getAge(String birthday) { if (birthday) { return getAge(formatDate(birthday)) } return 0 }
