reverse_re3-入土为安的第十天

import numpy as np
# 你的数据（长度应为 225 的倍数）
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]
# 矩阵的大小
n = 15
matrix_size = n * n
# 检查数组长度
length = len(dword_202020)
# 如果数据长度不足，填充到最近的矩阵大小的整数倍
if length < matrix_size:
    print(f"数据长度不足 ({length}), 将数据填充至 {matrix_size}")
    dword_202020 = dword_202020 + [0] * (matrix_size - length)  # 用 0 填充到最近的矩阵大小
elif length % matrix_size != 0:
    # 如果数据长度超过要求，截取到最近的矩阵大小的整数倍
    new_length = (length // matrix_size) * matrix_size
    print(f"数据长度超过 ({length}), 截取至 {new_length}")
    dword_202020 = dword_202020[:new_length]
# 转换为 numpy 数组
array = np.array(dword_202020)
# 计算每个矩阵的起始索引
matrices = [array[i:i + matrix_size].reshape(n, n) for i in range(0, len(array), matrix_size)]
# 打印矩阵
for idx, mat in enumerate(matrices):
    print(f"Matrix {idx + 1}:\n{mat}\n")