关于指针+1的奇葩习题

 #define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>
struct test
{
  int m;
  char* s;
  short p;
  char a[2];
    short q[4];
}*p;
int main()
{
  p = (struct test*)0x100000;
  printf("%p\n", p + 0x1);
//0x00 10 00 14 ->14等于十进制的20 即p原类型是一个结构体类型其大小为20byte所以当+1就会直接加20
  printf("%p\n", (unsigned long)p + 0x1);
//此处将p强转成了无符号的长整形既然是整形就直接+1即可
  printf("%p\n", (unsigned int *)p + 0x1);
//此处转化成了无符号int * 所以其大小又变成了4所以+1就是+4
  return 0;
}