# num = 10### def anum():#     num = 20#     print(num)### anum()num=3.14print("%.3f"%num)
# f"{变量:.nf}"print(f"{num:.3f}")  # 3.140num1=1# 00000001print('%6d'%num1)
print('%06d'%num1)  # 000001print(f'{num1:06d}')  # 000001

defget_age(num):
"""    求第 num 个人的年龄,每相邻的两个人的年龄差两岁, 已知第一个人的年龄是 18岁    :param num:    :return:    """ifnum==1:
return18# 求第 num个人的年龄,只需要num-1 这个人的年龄 + 2age=get_age(num-1) +2returnageprint(get_age(4))

deffunc(n):
num=1foriinrange(1, n+1):
num=num*iprint(num)
deffunc2(n):
ifn==1:
return1# 想要求 n! , 只需要(n-1)! * nnum=func2(n-1) *nreturnnum# func(5)print(func2(5))

deffunc(num):
ifnum==1:
return1sum=func(num-1) +numreturnsuma=func(100)
print(a)