每日一题<KY222 打印日期>

#include <iostream>
using namespace std;
int gtmd(int y,int m)
{
    int arr[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
    if(m==2 && (y%4==0&&y%100!=0||y%400==0))
    {
        return 29;
    }
    return arr[m];
}
int main() {
    int y,d,m;
    while(scanf("%d%d",&y,&d)!=EOF)
    {
        m = 1;
        int md =  gtmd(y,m);  //获得该年该月的天数
        while(d > md)       //表示第几天不能用等号
        {
            d-=md;
            m++;
            md = gtmd(y,m);
        }
        cout<<y<<'-';
        printf("%.2d-%.2d\n",m,d);
    }
}