【实用小脚本】Python暴力破解ZIP文件

# -*-coding:utf-8-*-
import itertools
import time
import zipfile

filepath = "文件路径"
uncompress_path = "解压路径"
# 密码位数
pwd_num_list = [3,4,5]
# 暴力破解全排列的字典
# pwd_dic = "abcdefghijklmnopqrstuvwxyz"
pwd_dic = "abcdefghijklmnopqrstuvwxyz0123456789"
# pwd_dic = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
# pwd_dic = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
# pwd_dic = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789~!@#$%^&*()_+-=<>."

def uncompress(filepath,password):
    try:
        with zipfile.ZipFile(filepath) as zFile:
            zFile.extractall(uncompress_path,pwd=password.encode("utf-8"))
        return True
        # if password=="1234":
        #     return True
    except:
        return False

count = 0
start_time = time.time()
for pwd_num in pwd_num_list:
    for c in itertools.permutations(pwd_dic, pwd_num):
        count += 1
        password = "".join(c)
        # print(password)
        if count % 10000 == 0:
            print("已尝试破解", count, "次")
        result = uncompress(filepath, password)
        if result:
            print("用时：", (time.time() - start_time), "秒")
            print("一共尝试了", count, "次")
            print("解压成功，密码是：", password)
            break